BreakIterator

A class that locates boundaries in text. This class defines a protocol for objects that break up a piece of natural-language text according to a set of criteria. Instances or subclasses of BreakIterator can be provided, for example, to break a piece of text into words, sentences, or logical characters according to the conventions of some language or group of languages.

We provide four built-in types of BreakIterator:

  • makeSentenceInstance() returns a BreakIterator that locates boundaries between sentences. This is useful for triple-click selection, for example.

  • makeWordInstance() returns a BreakIterator that locates boundaries between words. This is useful for double-click selection or "find whole words" searches. This type of BreakIterator makes sure there is a boundary position at the beginning and end of each legal word. (Numbers count as words, too.) Whitespace and punctuation are kept separate from real words.

  • makeLineInstance() returns a BreakIterator that locates positions where it is legal for a text editor to wrap lines. This is similar to word breaking, but not the same: punctuation and whitespace are generally kept with words (you don't want a line to start with whitespace, for example), and some special characters can force a position to be considered a line-break position or prevent a position from being a line-break position.

  • makeCharacterInstance() returns a BreakIterator that locates boundaries between logical characters. Because of the structure of the Unicode encoding, a logical character may be stored internally as more than one Unicode code point. (A with an umlaut may be stored as an a followed by a separate combining umlaut character, for example, but the user still thinks of it as one character.) This iterator allows various processes (especially text editors) to treat as characters the units of text that a user would think of as characters, rather than the units of text that the computer sees as "characters". The text boundary positions are found according to the rules described in Unicode Standard Annex #29, Text Boundaries, and Unicode Standard Annex #14, Line Breaking Properties. These are available at http://www.unicode.org/reports/tr14/ and http://www.unicode.org/reports/tr29/.

BreakIterator's interface follows an "iterator" model (hence the name), meaning it has a concept of a "current position" and methods like first(), last(), next(), and previous() that update the current position. All BreakIterators uphold the following invariants:

  • The beginning and end of the text are always treated as boundary positions.

  • The current position of the iterator is always a boundary position (random- access methods move the iterator to the nearest boundary position before or after the specified position, not to the specified position).

  • DONE is used as a flag to indicate when iteration has stopped. DONE is only returned when the current position is the end of the text and the user calls next(), or when the current position is the beginning of the text and the user calls previous().

  • Break positions are numbered by the positions of the characters that follow them. Thus, under normal circumstances, the position before the first character is 0, the position after the first character is 1, and the position after the last character is 1 plus the length of the string.

  • The client can change the position of an iterator, or the text it analyzes, at will, but cannot change the behavior. If the user wants different behavior, he must instantiate a new iterator.

BreakIterator accesses the text it analyzes through a CharacterIterator, which makes it possible to use BreakIterator to analyze text in any text-storage vehicle that provides a CharacterIterator interface.

Note: Some types of BreakIterator can take a long time to create, and instances of BreakIterator are not currently cached by the system. For optimal performance, keep instances of BreakIterator around as long as makes sense. For example, when word-wrapping a document, don't create and destroy a new BreakIterator for each line. Create one break iterator for the whole document (or whatever stretch of text you're wrapping) and use it to do the whole job of wrapping the text.

**Examples**:

Creating and using text boundaries

*
public static void main(String args[]) {
if (args.length == 1) {
String stringToExamine = args[0];
//print each word in order
BreakIterator boundary = BreakIterator.makeWordInstance();
boundary.setText(stringToExamine);
printEachForward(boundary, stringToExamine);
//print each sentence in reverse order
boundary = BreakIterator.makeSentenceInstance(Locale.US);
boundary.setText(stringToExamine);
printEachBackward(boundary, stringToExamine);
printFirst(boundary, stringToExamine);
printLast(boundary, stringToExamine);
}
}
*
*

Print each element in order

public static void printEachForward(BreakIterator boundary, String source) {
int start = boundary.first();
for (int end = boundary.next();
end != BreakIterator.DONE;
start = end, end = boundary.next()) {
System.out.println(source.substring(start,end));
}
}
*
*

Print each element in reverse order

public static void printEachBackward(BreakIterator boundary, String source) {
int end = boundary.last();
for (int start = boundary.previous();
start != BreakIterator.DONE;
end = start, start = boundary.previous()) {
System.out.println(source.substring(start,end));
}
}
*
*

Print first element

public static void printFirst(BreakIterator boundary, String source) {
int start = boundary.first();
int end = boundary.next();
System.out.println(source.substring(start,end));
}
*
*

Print last element

public static void printLast(BreakIterator boundary, String source) {
int end = boundary.last();
int start = boundary.previous();
System.out.println(source.substring(start,end));
}
*
*

Print the element at a specified position

public static void printAt(BreakIterator boundary, int pos, String source) {
int end = boundary.following(pos);
int start = boundary.previous();
System.out.println(source.substring(start,end));
}
*
*

Find the next word

public static int nextWordStartAfter(int pos, String text) {
BreakIterator wb = BreakIterator.makeWordInstance();
wb.setText(text);
int wordStart = wb.following(pos);
for (;;) {
int wordLimit = wb.next();
if (wordLimit == BreakIterator.DONE) {
return BreakIterator.DONE;
}
int wordStatus = wb.getRuleStatus();
if (wordStatus != BreakIterator.WORD_NONE) {
return wordStart;
}
wordStart = wordLimit;
}
}
* The iterator returned by [.makeWordInstance] is unique in that the break positions it returns don't represent both the start and end of the thing being iterated over. That is, a sentence-break iterator returns breaks that each represent the end of one sentence and the beginning of the next. With the word-break iterator, the characters between two boundaries might be a word, or they might be the punctuation or whitespace between two words. The above code uses [.getRuleStatus] to identify and ignore boundaries associated with punctuation or other non-word characters.
*

Types

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object Companion

Properties

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expect open val isClosed: Boolean

Check if underlying resource is closed.

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For rule-based BreakIterators, return the status tag from the break rule that determined the boundary at the current iteration position.

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For RuleBasedBreakIterators, get the status (tag) values from the break rule(s) that determined the the boundary at the current iteration position.

Functions

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Create a copy of this iterator

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open override fun close()

Free underlying native resource, peer is useless afterwards.

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fun current(): Int

Returns character index of the text boundary that was most recently returned by [], [], [], [], [], [] or []. If any of these methods returns BreakIterator.DONE because either first or last text boundary has been reached, it returns the first or last text boundary depending on which one is reached.

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fun first(): Int

Returns the first boundary. The iterator's current position is set to the first text boundary.

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fun following(offset: Int): Int

Returns the first boundary following the specified character offset. If the specified offset is equal to the last text boundary, it returns BreakIterator.DONE and the iterator's current position is unchanged. Otherwise, the iterator's current position is set to the returned boundary. The value returned is always greater than the offset or the value BreakIterator.DONE.

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fun isBoundary(offset: Int): Boolean

Returns true if the specified character offset is a text boundary.

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fun last(): Int

Returns the last boundary. The iterator's current position is set to the last text boundary.

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operator fun next(): Int

Returns the boundary following the current boundary. If the current boundary is the last text boundary, it returns BreakIterator.DONE and the iterator's current position is unchanged. Otherwise, the iterator's current position is set to the boundary following the current boundary.

fun next(index: Int): Int

Advances the iterator either forward or backward the specified number of steps. Negative values move backward, and positive values move forward. This is equivalent to repeatedly calling next() or previous().

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fun preceding(offset: Int): Int

Returns the last boundary preceding the specified character offset. If the specified offset is equal to the first text boundary, it returns BreakIterator.DONE and the iterator's current position is unchanged. Otherwise, the iterator's current position is set to the returned boundary. The value returned is always less than the offset or the value BreakIterator.DONE.

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fun previous(): Int

Returns the boundary following the current boundary. If the current boundary is the last text boundary, it returns BreakIterator.DONE and the iterator's current position is unchanged. Otherwise, the iterator's current position is set to the boundary following the current boundary.

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fun setText(text: String?)

Set a new text string to be scanned. The current scan position is reset to [].

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expect open override fun toString(): String